Question :
Number of cars | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 | 60 – 70 | 70 – 80 |
Frequency | 7 | 14 | 13 | 12 | 20 | 11 | 15 | 8 |
Solution :
The class (40 – 50) has the maximum frequency frequency. Therefore, this is the modal class.
Here, l = 40, h = 10, \(f_1\) = 20, \(f_0\) = 12 and \(f_2\) = 11
Now, let us substitute these values in the formula
Mode = l + (\(f_1 – f_0\over 2f_1 – f_0 – f_2\)) \(\times\) h
Mode = 40 + (\(20 – 12\over 40 – 12 – 11\)) \(\times\) 10
Mode = 40 + 4.7 = 44.7
Hence, mode = 44.7 cars