Prove that \(Cosec(90 – \theta)\) = \(Sec\theta\).
Solution : Draw a right angled triangle ABC right angled at B. Let \(\angle\) A = \(\theta\), then \(\angle\) C = 90 – \(\theta\) sec A = \(sec\theta\) = \(AC\over AB\) ……..(1) cosec C = \(cosec(90 – \theta)\) = \(AC\over AB\) …
Prove that \(Cosec(90 – \theta)\) = \(Sec\theta\). Read More »