mathemerize

What is the Value of Cot 60 Degrees ?

Solution : The value of cot 60 degrees is \(1\over \sqrt{3}\). Proof : Consider an equilateral triangle ABC with each side of length of 2a. Each angle of \(\Delta\) ABC is of 60 degrees. Let AD be the perpendicular from A on BC. \(\therefore\)   AD is the bisector of \(\angle\) A and D is the mid-point …

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What is the Value of Cos 60 Degrees ?

Solution : The value of Cos 60 degrees is \(1\over 2\). Proof : Consider an equilateral triangle ABC with each side of length of 2a. Each angle of \(\Delta\) ABC is of 60 degrees. Let AD be the perpendicular from A on BC. \(\therefore\)   AD is the bisector of \(\angle\) A and D is the …

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What is the Value of Sin 60 Degrees ?

Solution : The value of sin 60 degrees is \(\sqrt{3}\over 2\). Proof : Consider an equilateral triangle ABC with each side of length of 2a. Each angle of \(\Delta\) ABC is of 60 degrees. Let AD be the perpendicular from A on BC. \(\therefore\)   AD is the bisector of \(\angle\) A and D is the …

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What is the Value of Sec 30 Degrees ?

Solution : The value of sec 30 degrees is \(2\over \sqrt{3}\). Proof : Consider an equilateral triangle ABC with each side of length of 2a. Each angle of \(\Delta\) ABC is of 60 degrees. Let AD be the perpendicular from A on BC. \(\therefore\)   AD is the bisector of \(\angle\) A and D is the …

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What is the Value of Tan 30 Degrees ?

Solution : The value of tan 30 degrees is \(1\over \sqrt{3}\). Proof : Consider an equilateral triangle ABC with each side of length of 2a. Each angle of \(\Delta\) ABC is of 60 degrees. Let AD be the perpendicular from A on BC. \(\therefore\)   AD is the bisector of \(\angle\) A and D is the mid-point …

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What is the Value of Cos 30 Degrees ?

Solution : The value of cos 30 degrees is \(\sqrt{3}\over 2\). Proof : Consider an equilateral triangle ABC with each side of length of 2a. Each angle of \(\Delta\) ABC is of 60 degrees. Let AD be the perpendicular from A on BC. \(\therefore\)   AD is the bisector of \(\angle\) A and D is the mid-point …

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