Solution : We have, I = \(cos^{-1}\sqrt{x}\) . 1 dx By Applying integration by parts, Taking \(cos^{-1}\sqrt{x}\) as first function and 1 as second function. Then I = \(cos^{-1}\sqrt{x}\) \(\int\) 1 dx โ \(\int\) {\(d\over dx\)\(cos^{-1}\sqrt{x}\) \(\int\) 1 dx } dx I = x\(cos^{-1}\sqrt{x}\) โ \(\int\) \(-1\over 2\sqrt{(1-x)}\sqrt{x}\) . x dx I = x\(cos^{-1}\sqrt{x}\) โ โฆ
What is the integration of cos inverse root x ? Read More ยป
Solution : We have, I = \(\int\)ย \(x cos^{-1} x\) dx By using integration by parts formula, I = \(cos^{-1} x\) \(x^2\over 2\) โ \(\int\) \(-1\over \sqrt{1 โ x^2}\) \(\times\) \(x^2\over 2\) dx I =ย \(x^2\over 2\) \(cos^{-1} x\) โ \(1\over 2\) \(\int\) \(-x^2\over \sqrt{1 โ x^2}\) dx = \(x^2\over 2\) \(cos^{-1} x\) โ \(1\over โฆ
Solution : We have, I = \(\int\) \(sin^{-1}(cos x)\) dx By using integration formula, cos x = \(sin({\pi\over 2} โ x)\) I = \(\int\) \(sin^{-1}[sin({\pi\over 2} โ x)]\) dx I = \(\int\) \(({\pi\over 2} โ x)\) dx I = \({\pi\over 2}x\) โ \(x^2\over 2\) + C Similar Questions What is the integration of sin inverse โฆ
Solution : We have, I = \(sin^{-1}\sqrt{x}\) . 1 dx By Applying integration by parts, Taking \(sin^{-1}\sqrt{x}\) as first function and 1 as second function. Then I = \(sin^{-1}\sqrt{x}\) \(\int\) 1 dx โ \(\int\) {\(d\over dx\)\(sin^{-1}\sqrt{x}\) \(\int\) 1 dx } dx I = x\(sin^{-1}\sqrt{x}\) โ \(\int\) \(1\over 2\sqrt{(1-x)}\sqrt{x}\) . x dx I = x\(sin^{-1}\sqrt{x}\) โ โฆ
What is the integration of sin inverse root x ? Read More ยป
Solution : We have, I = \((sin^{-1}x)^2\) dx Let \(sin^{-1}x\) = t, Then, x = sin t \(\implies\) dx = cos t dt \(\therefore\) I = \(\int\) \((sin^{-1}x)^2\) dx I = \(\int\) \(t^2\) cos t dt Applying integration by parts and, Taking \(t^2\) as first function and cos t as second function, I = \(t^2\) โฆ
What is the integration of sin inverse x whole square ? Read More ยป
Solution : We have, I = \(\int\)ย \(x sin^{-1} x\) dx By using integration by parts formula, I = \(sin^{-1} x\) \(x^2\over 2\) โ \(\int\) \(1\over \sqrt{1 โ x^2}\) \(\times\) \(x^2\over 2\) dx I =ย \(x^2\over 2\) \(sin^{-1} x\) + \(1\over 2\) \(\int\) \(-x^2\over \sqrt{1 โ x^2}\) dx = \(x^2\over 2\) \(sin^{-1} x\) + \(1\over โฆ
What is the integration of x sin inverse x dx ? Read More ยป
Solution : The formula for volume of cuboid of length l, breadth b and height h is \(lbh\). Read Post : Formula for Volume of cuboid โ Derivation & Example Similar Questions What is the Formula for Surface Area of Cylinder ? What is the Formula for Surface Area of Cube ? What is the โฆ
Solution : The formula for the total suface area of cube of side a is \(6a^2\). And the formula for the lateral surface area of cube is \(4a^2\). Read Post : Formula for Surface Area of Cube โ Derivation & Example Similar Questions What is the Formula for Volume of Cuboid ? What is the โฆ
Solution : The formula for surface area of a cuboid of length l, breadth b and height h is 2(lb + bh + hl). This is the total surface area of cuboid. The lateral surface area of cuboid is 2(l + b)h. Read Post : Formula for Surface Area of Cuboid โ Derivation & Example โฆ
What is the Formula for Surface Area of a Cuboid ? Read More ยป
Solution : The formula for volume of a cube of side a is \(a^3\). Read Post : Formula for Volume of Cube โ Derivation & Example Similar Questions What is the Formula for Volume of Cuboid ? What is the Formula for Surface Area of Cube ? What is the Formula for Surface Area of โฆ
