Solution :
Solving the curves simultaneously we get points of intersection as (1, 1) and (0, 0).
At (1, 1) for first curve \(2y({dy\over dx})_1\) = 1 \(\implies\) \(m_1\) = \(1\over 2\)
& for second curve 2x = \(({dy\over dx})_2\) \(\implies\) \(m_2\) = 2
\(m_1m_2\) = -1 at (1, 1).
But at (0, 0) clearly x-axis & y-axis are their respective tangents hence they are orthogonal at (0, 0) but not at (1, 1). Hence these curves are not said to be orthogonal.
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