Find the coordinates of the point of intersecton of the lines 2x – y + 3 = 0 and x + y – 5 = 0.

Solution :

Solving simultaneously the equations 2x – y + 3 = 0 and x + y – 5 = 0, we obtain

\(x\over {5 – 3}\) = \(y\over {3 + 10}\) = \(1\over {2 + 1}\)

\(\implies\) \(x\over 2\) = \(y\over 13\) = \(1\over 3\)

\(\implies\) x = \(2\over 3\) , y = \(13\over 3\)

Hence, (2/3, 13/3) is the required point of intersection.


Similar Questions

Find the equation of line joining the point (3, 5) to the point of intersection of the lines 4x + y – 1 = 0 and 7x – 3y – 35 = 0.

Find the equation of line parallel to y-axis and drawn through the point of intersection of the lines x – 7y + 5 = 0 and 3x + y = 0.

Find the equation of lines which passes through the point (3,4) and the sum of intercepts on the axes is 14.

The slope of tangent parallel to the chord joining the points (2, -3) and (3, 4) is

Leave a Comment

Your email address will not be published. Required fields are marked *

Ezoicreport this ad