Solution :
f(x) = \(3x^4 – 4x^3\)
f'(x) = \(12x^3 – 12x^2\)
f'(x) = \(12x^2(x – 1)\)
Now, f”(x) = \(12(3x^2 – 2x)\)
f”(x) = 12x(3x – 2)
f”(x) = 0 \(\implies\) x = 0, 2/3
Here, f”(x) = 0
Thus, x = 0, 2/3 are the inflection points.
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