Solution :
f(x) = \(e^{x-[x]+|cos\pi x|+|cos2\pi x|+ ….. + |cosn\pi x|}\)
Period of x – [x] = 1
Period of \(|cos\pi x|\) = 1
Period of \(|cos2\pi x|\) = \(1\over 2\)
……………………………….
Period of \(|cosn\pi x|\) = \(1\over n\)
So period of f(x) will be L.C.M of all period = 1.
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