Given H.C.F. (306, 657) = 9, find L.C.M. (306, 657).

Solution :

We have, H.C.F. (306, 657) = 9.

We know that,

Product of L.C.M and H.C.F = Product of two numbers.

\(\implies\)  L.C.M \(\times\) 9 = \(306 \times 657\)

\(\implies\)  L.C.M = \(306 \times 657 \over 9\) = 22338

Hence, L.C.M is 22338.