Solution :
Since by deleting a single term from an infinite series, it remains same. Therefore, the given function may be written as
y = \(\sqrt{sin x + y}\)
Squaring on both sides,
\(\implies\) \(y^2\) = sin x + y
By using differentiation of infinite series,
Differentiating both sides with respect to x,
2y \(dy\over dx\) =cosx + \(dy\over dx\)
\(\implies\) \(dy\over dx\)\((2y – 1)\) = cos x
\(\implies\) \(dy\over dx\) = \(cos x\over {2y – 1}\)
