In figures, (i) and (ii) DE || BC. Find EC in (i) and AD in (ii).

Solution :

(i)  In figure (i)

Since DE || BC, therefore

\(AD\over DB\) = \(AE\over EC\)

\(\implies\)  \(1.5\over 3\) = \(1\over EC\)

\(\implies\)  EC = 2 cm.

(ii)  In figure (ii),

Since DE || BC, therefore

\(AD\over DB\) = \(AE\over EC\)

\(\implies\)  \(AD\over 7.2\) = \(1.8\over 5.4\)

\(\implies\)  AD = 2.4 cm.