Solution :
Let us draw a right \(\triangle\) ABC,
By using Pythagoras Theorem, we have :
\({AC}^2\) = \({AB}^2\) + \({BC}^2\) = \((24)^2\) + \((7)^2\)
= 576 + 49 = 625
So, AC = \(\sqrt{625}\) = 25 cm
(i) Sin A = \(BC\over AB\) = \(7\over 25\), Cos A = \(AB\over AC\) = \(24\over 25\)
(ii) Sin C = \(AB\over AC\) = \(24\over 25\), Cos C = \(BC\over AC\) = \(7\over 25\)