Solution :
Let O be the position of nazima at the time of fishing.
Let OA be the rod and AB be the string.
Height of the tip of rod above sea level.
i.e. AC = 1.8 m
The distance of the fly from the girl = 3.6 m
i.e. OB = 3.6 m
In triangle ABC,
\({AB}^2\) = \({CB}^2\) + \({AC}^2\) = \((3.6 – 1.2)^2\) + \((1.5)^2\)
= 5.76 + 3.24 = 9 m
\(\implies\) AB = 3 m
The rate of pulling the string = 5 cm/sec.
In 12 sec, the girl will pull = 12 \(\times\) 5 = 60 cm
The remaining length of the string AD = 3 – 0.6 = 2.4 m
New position of the string is AD.
In right triangle ACD,
\({CD}^2\) = \({AD}^2\) – \({AC}^2\)
= 5.76 – 3.24 = 2.52
CD = 1.6 m
OD = distance of the fly from her
\(\implies\) OD = OC + CD = 1.2 + 1.6 = 2.8 m