Solution :
The given linear equations are :
8x + 5y = 9 ………..(1)
3x + 2y = 4 ………..(2)
By Substitution Method :
Form equation (1), y = \(9 – 8x\over 5\)
Substitute the value of y in equation (2), we get
3x + 2(\(9 – 8x\over 5\)) = 4
or 15x + 18 – 16x = 20 \(\implies\) x = -2
Putting x = – 2 in equation (1), we get
8(-2) + 5y = 9 \(\implies\) 5y = 9 + 16 = 25
\(\implies\) y = 5
Hence, x = -2 and y = 5.
By Cross-Multiplication Method :
The given linear equation can be written as :
8x + 5y – 9 = 0
3x + 2y – 4 = 0
So, we have
\(x\over -20 + 18\) = \(y\over -27 + 32\) = \(1\over 16 – 15\)
\(\implies\) \(x\over -2\) = \(y\over 5\) = \(1\over 1\)
\(\implies\) x = -2 and y = 5
