Solution :
Let the equation of the ellipse be \(x^2\over a^2\) + \(y^2\over b^2\) = 1.
Then, coordinates of the foci are \((\pm ae, 0)\).
Therefore, ae = 2 \(\implies\) a = 4
We have \(b^2\) = \(a^2(1 – e^2)\) \(\implies\) \(b^2\) =12
Thus, the equation of the ellipse is \(x^2\over 16\) + \(y^2\over 12\) = 1
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