The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is 18 rupees. Find the missing frequency f.

Question :

Class Interval 11 – 13 13 – 15 15 – 17 17 – 19 19 – 21 21 – 23 23 – 25
Frequency 7 6 9 13 f 5 4

Solution :

We have,

Class Interval Mid-value (\(x_i\)) Frequency (\(f_i\)) \(f_ix_i\)
11 – 13 12 7 84
13 – 15 14 6 84
15 – 17 16 9 144
17 – 19 18 13 234
19 – 21 20 f 20 f
21 – 23 22 5 110
23 – 25 24 4 90
\(\sum f_i\) = 44 + f \(\sum f_ix_i\) = 752 + 20f

So, Mean (\(\bar{x}\)) = \(\sum f_ix_i\over f_i\) = \(752 + 20f\over 44 + f\)

\(\implies\) 18 = \(752 + 20f\over 44 + f\)

\(\implies\) 752 + 20f = 792 + 18f

\(\implies\) 2f = 40

\(\implies\) f = 20

Hence, the missing frequency is 20.

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