Question :
Class Interval | 11 – 13 | 13 – 15 | 15 – 17 | 17 – 19 | 19 – 21 | 21 – 23 | 23 – 25 |
Frequency | 7 | 6 | 9 | 13 | f | 5 | 4 |
Solution :
We have,
Class Interval | Mid-value (\(x_i\)) | Frequency (\(f_i\)) | \(f_ix_i\) |
11 – 13 | 12 | 7 | 84 |
13 – 15 | 14 | 6 | 84 |
15 – 17 | 16 | 9 | 144 |
17 – 19 | 18 | 13 | 234 |
19 – 21 | 20 | f | 20 f |
21 – 23 | 22 | 5 | 110 |
23 – 25 | 24 | 4 | 90 |
\(\sum f_i\) = 44 + f | \(\sum f_ix_i\) = 752 + 20f |
So, Mean (\(\bar{x}\)) = \(\sum f_ix_i\over f_i\) = \(752 + 20f\over 44 + f\)
\(\implies\) 18 = \(752 + 20f\over 44 + f\)
\(\implies\) 752 + 20f = 792 + 18f
\(\implies\) 2f = 40
\(\implies\) f = 20
Hence, the missing frequency is 20.