Question :
| Runs scored | Number of batsmen |
| 3000 – 4000 | 4 |
| 4000 – 5000 | 18 |
| 5000 – 6000 | 9 |
| 6000 – 7000 | 7 |
| 7000 – 8000 | 6 |
| 8000 – 9000 | 3 |
| 9000 – 10000 | 1 |
| 10000 – 11000 | 1 |
Solution :
The class (4000 – 5000) has the maximum frequency. Therefore, this is the modal class.
Here, l = 4000, h = 1000, \(f_1\) = 18, \(f_0\) = 4 and \(f_2\) = 9
Now, let us substitute these values in the formula
Mode = l + (\(f_1 – f_0\over 2f_1 – f_0 – f_2\))\(\times\)h
Mode = 4000 + \(18 – 4\over 36 – 4 – 9\)\(\times\) 1000
Mode = 4000 + 608.695 = 4608.695
Thus, the mode of the given data is 4608.7 runs.
