The number of ways of distributing 8 identical balls in 3 distinct boxes, so that none of the boxes is empty, is

Solution :

The number of ways of distributing n identical things in m different boxes is \(^{n-1}C_{m-1}\)

So, Required number of ways = \(^{8-1}C_{3-1}\)

= \(^7C_2\)

= 21

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