Solution :
Given, probabilities of speaking truth are
P(A) = \(4\over 5\) and P(B) = \(3\over 4\)
And their corresponding probabilities of not speaking truth are
P(A’) = \(1\over 5\) and P(B’) = \(1\over 4\)
The probability that they contradict each other
= P(A).P(B’) + P(B).P(A’)
= \(4\over 5\) \(\times\) \(1\over 4\) + \(1\over 5\) \(\times\) \(3\over 4\)
= \(7\over 20\)