Solution :
We have,ย ย area of triangle ABC = 64 \(cm^2\)
and area of triangle DEF = 121 \(cm^2\)
We know that,
\(ar(\triangle ABC)\over ar(\triangle DEF)\) = \(({BC\over EF})^2\)
\(\implies\)ย \(64\over 121\) = \(({BC\over 15.4})^2\)
\(\implies\) \(8\over 11\) = \(BC\over 15.4\)
\(\implies\) BC = 11.2 cm.