Solution :
We have, I = \(\int\) \(sin^{-1}(cos x)\) dx
By using integration formula, cos x = \(sin({\pi\over 2} โ x)\)
I = \(\int\) \(sin^{-1}[sin({\pi\over 2} โ x)]\) dx
I = \(\int\) \(({\pi\over 2} โ x)\) dx
I = \({\pi\over 2}x\) โ \(x^2\over 2\) + C
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