Solution :
The value of cot 90 degrees is 0.
Proof :
\(\angle\) A of \(\Delta\) ABC is made large and large until it becomes 90 degrees. As \(\angle\) A gets large and large \(\angle\) C gets smaller and smaller. Side AB goes on decreasing. The point A gets closer to point B. When \(\angle\) C becomes very close to 0 degree. The side AC almost coincide with side BC and side AB becomes to zero.
So, AC = BC and AB = 0
By using trigonometric formulas,
\(cot 90^{\circ}\) = \(base\over perpendicular\) = \(b\over p\)
\(cot 90^{\circ}\) = \(AB\over BC\) = \(0\over BC\) = 0
Hence, the value of \(cot 90^{\circ}\) = 0.
