{"id":10371,"date":"2022-04-03T21:57:46","date_gmt":"2022-04-03T16:27:46","guid":{"rendered":"https:\/\/mathemerize.com\/?p=10371"},"modified":"2022-04-05T18:23:31","modified_gmt":"2022-04-05T12:53:31","slug":"express-each-number-as-a-product-of-its-prime-factors","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/express-each-number-as-a-product-of-its-prime-factors\/","title":{"rendered":"Express each number as a product of its prime factors :"},"content":{"rendered":"

Question<\/strong> : Express each number as a product of its prime factors :<\/p>\n

(i) 140<\/p>\n

(ii) 156<\/p>\n

(iii) 3825<\/p>\n

(iv) 5005<\/p>\n

(v) 7429<\/p>\n

Solution<\/strong> :<\/p>\n

(i)\u00a0\u00a0<\/strong>We use the division method as shown below :<\/p>\n

\\(\\therefore\\)\u00a0 \u00a0140 = \\(2 \\times 2 \\times 5 \\times 7\\)<\/p>\n

= \\(2^2 \\times 5 \\times 7\\)<\/strong><\/p>\n

(ii)\u00a0 <\/strong>We use the division method as shown below :<\/p>\n

\\(\\therefore\\)\u00a0 \u00a0156 = \\(2 \\times 2 \\times 3 \\times 13\\)<\/p>\n

= \\(2^2 \\times 3 \\times 13\\)<\/strong><\/p>\n

(iii)\u00a0 <\/strong>We use the division method as shown below :<\/p>\n

\\(\\therefore\\)\u00a0 \u00a03825 = \\(3 \\times 3 \\times 5 \\times 5 \\times 17\\)<\/p>\n

= \\(3^2 \\times 5^2 \\times 17\\)<\/strong><\/p>\n

(iv)\u00a0 <\/strong>We use the division method as shown below :<\/p>\n

\\(\\therefore\\)\u00a0 \u00a05005 = \\(5 \\times 7 \\times 11 \\times 13\\)<\/p>\n

= \\(5 \\times 7 \\times 11\\times 13\\)<\/strong><\/p>\n

(v)\u00a0 <\/strong>We use the division method as shown below :<\/p>\n

\\(\\therefore\\)\u00a0 \u00a07429 = \\(17 \\times 19 \\times 23\\)<\/p>\n

= \\(17 \\times 19 \\times 23\\)<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

Question : Express each number as a product of its prime factors : (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429 Solution : (i)\u00a0\u00a0We use the division method as shown below : \\(\\therefore\\)\u00a0 \u00a0140 = \\(2 \\times 2 \\times 5 \\times 7\\) = \\(2^2 \\times 5 \\times 7\\) (ii)\u00a0 We use the division …<\/p>\n

Express each number as a product of its prime factors :<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,909],"tags":[],"yoast_head":"\nExpress each number as a product of its prime factors : - Mathemerize<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/express-each-number-as-a-product-of-its-prime-factors\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Express each number as a product of its prime factors : - 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