{"id":10374,"date":"2022-04-04T00:34:38","date_gmt":"2022-04-03T19:04:38","guid":{"rendered":"https:\/\/mathemerize.com\/?p=10374"},"modified":"2022-04-05T18:23:22","modified_gmt":"2022-04-05T12:53:22","slug":"find-the-l-c-m-and-h-c-f-of-the-following-pairs-of-integers-and-verify","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/find-the-l-c-m-and-h-c-f-of-the-following-pairs-of-integers-and-verify\/","title":{"rendered":"Find the L.C.M and H.C.F of the following pairs of integers and verify :"},"content":{"rendered":"
Question<\/strong> : Find the L.C.M and H.C.F of the following pairs of integers and verify :<\/p>\n L.C.M \\(\\times\\) H.C.F = Product of the two numbers<\/p>\n (i) 26 and 91<\/p>\n (ii) 510 and 92<\/p>\n (iii) 336 and 54<\/p>\n Solution<\/strong> : <\/p>\n (i) <\/strong> 26 and 91<\/p>\n 26 = 2 \\(\\times\\) 13 and 91 = 7 \\(\\times\\) 13<\/p>\n \\(\\therefore\\) L.C.M of 26 and 91 = 2 \\(\\times\\) 7 \\(\\times\\) 13 = 182<\/p>\n and H.C.F of 26 and 91 = 13<\/p>\n Now, 182 \\(\\times\\) 13 = 2366 and 26 \\(\\times\\) 91 = 2366<\/p>\n Hence, 182 \\(\\times\\) 13 = 26 \\(\\times\\) 91<\/strong><\/p>\n (ii) <\/strong> 510 and 92<\/p>\n 510 = 2 \\(\\times\\) 3 \\(\\times\\) 5 \\(\\times\\) 17 and 92 = 2 \\(\\times\\) 2 \\(\\times\\) 23<\/p>\n \\(\\therefore\\) L.C.M of 510 and 92 = 2 \\(\\times\\) 2 \\(\\times\\) 3 \\(\\times\\) 5 \\(\\times\\) 17 \\(\\times\\) 23 = 23460<\/p>\n and H.C.F of 510 and 92 = 2<\/p>\n Now, 23460 \\(\\times\\) 2 = 46920 and 510 \\(\\times\\) 92 = 46920<\/p>\n Hence, 23460 \\(\\times\\) 2 = 510 \\(\\times\\) 92<\/strong><\/p>\n (iii) <\/strong> 336 and 54<\/p>\n 336 = 2 \\(\\times\\) 2 \\(\\times\\) 2 \\(\\times\\) 2 \\(\\times\\) 3 \\(\\times\\) 7<\/p>\n and 54 = 2 \\(\\times\\) 3 \\(\\times\\) 3 \\(\\times\\) 3<\/p>\n \\(\\therefore\\) L.C.M of 336 and 54 = 2 \\(\\times\\) 2 \\(\\times\\) 2 \\(\\times\\) 2 \\(\\times\\) 3 \\(\\times\\) 3 \\(\\times\\) 3 \\(\\times\\) 7 = 3024<\/p>\n and H.C.F of 336 and 54 = 2 \\(\\times\\) 3 = 6<\/p>\n Now, 3024 \\(\\times\\) 6 = 18144 and 336 \\(\\times\\) 54 = 18144<\/p>\n Hence, 3024 \\(\\times\\) 6 = 336 \\(\\times\\) 54<\/strong><\/p>\n\n\n <\/p>\n","protected":false},"excerpt":{"rendered":" Question : Find the L.C.M and H.C.F of the following pairs of integers and verify : L.C.M \\(\\times\\) H.C.F = Product of the two numbers (i) 26 and 91 (ii) 510 and 92 (iii) 336 and 54 Solution : (i) 26 and 91 26 = 2 \\(\\times\\) 13 and 91 …<\/p>\n