{"id":10796,"date":"2022-05-30T01:59:45","date_gmt":"2022-05-29T20:29:45","guid":{"rendered":"https:\/\/mathemerize.com\/?p=10796"},"modified":"2022-05-30T01:59:49","modified_gmt":"2022-05-29T20:29:49","slug":"on-dividing-x3-3x2-x-2-by-a-polynomial-gx-the-quotient-and-the-remainder-were-x-2-and-2x-4-respectively-find-gx","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/on-dividing-x3-3x2-x-2-by-a-polynomial-gx-the-quotient-and-the-remainder-were-x-2-and-2x-4-respectively-find-gx\/","title":{"rendered":"On dividing \\(x^3 – 3x^2 + x + 2\\) by a polynomial g(x), the quotient and the remainder were x – 2 and -2x + 4, respectively. Find g(x)."},"content":{"rendered":"
Question<\/strong> : On dividing \\(x^3 – 3x^2 + x + 2\\) by a polynomial g(x), the quotient and the remainder were x – 2 and -2x + 4, respectively. Find g(x).<\/p>\n p(x) = \\(x^3 – 3x^2 + x + 2\\)<\/p>\n q(x) = x – 2 and r(x) = -2x + 4<\/p>\n Solution<\/strong> : By division algorithm, we know that<\/p>\n p(x) = q(x) \\(\\times\\) g(x) + r(x)<\/p>\n Therefore, \\(x^3 – 3x^2 + x + 2\\) = (x – 2) \\(\\times\\) g(x) + (-2x + 4)<\/p>\n \\(\\implies\\) \\(x^3 – 3x^2 + x + 2 + 2x – 4\\) = (x – 2) \\(\\times\\) g(x)<\/p>\n \\(\\implies\\)\u00a0 g(x) = \\(x^3 – 3x^2 + 3x – 2\\over x – 2\\)<\/p>\n On dividing\u00a0 \\(x^3 – 3x^2 + x + 2\\) by x – 2, we get g(x)<\/p>\n <\/p>\n Hence, g(x) = \\(x^2 – x + 1\\)<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Question : On dividing \\(x^3 – 3x^2 + x + 2\\) by a polynomial g(x), the quotient and the remainder were x – 2 and -2x + 4, respectively. Find g(x). p(x) = \\(x^3 – 3x^2 + x + 2\\) q(x) = x – 2 and r(x) = -2x + 4 Solution : By division …<\/p>\n