{"id":10824,"date":"2022-05-31T13:35:13","date_gmt":"2022-05-31T08:05:13","guid":{"rendered":"https:\/\/mathemerize.com\/?p=10824"},"modified":"2022-05-31T13:35:17","modified_gmt":"2022-05-31T08:05:17","slug":"if-two-zeroes-of-the-polynomial-x4-6x3-26x2-138x-35-are-2-pm-sqrt3-find-other-zeroes","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/if-two-zeroes-of-the-polynomial-x4-6x3-26x2-138x-35-are-2-pm-sqrt3-find-other-zeroes\/","title":{"rendered":"If two zeroes of the polynomial \\(x^4 – 6x^3 – 26x^2 + 138x – 35\\) are \\(2 \\pm \\sqrt{3}\\), find other zeroes."},"content":{"rendered":"
We have : \\(2 \\pm \\sqrt{3}\\) are two zeroes of the polynomial<\/p>\n
p(x) = \\(x^4 – 6x^3 – 26x^2 + 138x – 35\\)<\/p>\n
Let x = \\(2 \\pm \\sqrt{3}\\),\u00a0 So, x – 2 = \\(\\pm \\sqrt{3}\\)<\/p>\n
Squaring, we get<\/p>\n
\\(x^2 – 4x + 4\\) = 3,\u00a0 \u00a0i.e.\u00a0 \\(x^2 – 4x + 1\\) = 0<\/p>\n
Let us divide p(x) by \\(x^2 – 4x + 1\\) to obtain other zeroes.<\/p>\n
<\/p>\n
\\(\\therefore\\)\u00a0 p(x) = \\(x^4 – 6x^3 – 26x^2 + 138x – 35\\)<\/p>\n
= (\\(x^2 – 4x + 1\\))(\\(x^2 – 2x – 35\\))<\/p>\n
= (\\(x^2 – 4x + 1\\))(\\(x^2 – 7x + 5x – 35\\))<\/p>\n
= (\\(x^2 – 4x + 1\\))(x + 5)(x – 7)<\/p>\n
So, (x+ 5) and (x – 7) are the other factors of p(x).<\/p>\n
\\(\\therefore\\)\u00a0 \u00a0 -5\u00a0 and 7 are other zeroes of the given polynomial<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Solution : We have : \\(2 \\pm \\sqrt{3}\\) are two zeroes of the polynomial p(x) = \\(x^4 – 6x^3 – 26x^2 + 138x – 35\\) Let x = \\(2 \\pm \\sqrt{3}\\),\u00a0 So, x – 2 = \\(\\pm \\sqrt{3}\\) Squaring, we get \\(x^2 – 4x + 4\\) = 3,\u00a0 \u00a0i.e.\u00a0 \\(x^2 – 4x + 1\\) = …<\/p>\n