{"id":10841,"date":"2022-06-02T20:24:27","date_gmt":"2022-06-02T14:54:27","guid":{"rendered":"https:\/\/mathemerize.com\/?p=10841"},"modified":"2022-06-02T20:26:02","modified_gmt":"2022-06-02T14:56:02","slug":"aftab-tells-his-daughter-seven-years-ago-i-was-seven-times-as-old-as-you-were-then-also-three-years-from-now-i-shall-be-three-times-as-old-as-you-will-be","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/aftab-tells-his-daughter-seven-years-ago-i-was-seven-times-as-old-as-you-were-then-also-three-years-from-now-i-shall-be-three-times-as-old-as-you-will-be\/","title":{"rendered":"Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.”"},"content":{"rendered":"\n
Question<\/strong> : Aftab tells his daughter, “Seven years ago, I was seven times as old as you were then. Also, three years from now, I shall be three times as old as you will be.” (Isn’t this interesting?) Represent this situation algebraically and graphically.<\/p>\n\n\n\n Solution<\/strong> : Let the present age of father be x years and the age of daughter be y years<\/p>\n\n\n\n Seven years ago fathers’s age = (x – 7) years<\/p>\n\n\n\n Seven years ago daughter’s age = (y – 7) years<\/p>\n\n\n\n According to problem,<\/p>\n\n\n\n (x – 7) = 7(y – 7) or x – 7y = -42 ………….(1)<\/p>\n\n\n\n After three years father’s age = (x + 3) years<\/p>\n\n\n\n After three years daughter’s age = (y + 3) years<\/p>\n\n\n\n According to the condition given in the question,<\/p>\n\n\n\n (x +3) = 3(y + 3) or x – 3y = 6 …………..(2)<\/p>\n\n\n\n For (x – 7y = -42)<\/p>\n\n\n\n For x – 3y = 6<\/p>\n\n\n\n Plot the points A(0, 6), B(7, 7), C(4,8) and join them to get a straight line ABC. Similarly plot the points D(6, 0), E(12, 2) and F(18, 4) and join them to get a straight line DEF.<\/p>\n\n\n\nx<\/td> 0<\/td> 6<\/td> 14<\/td><\/tr> y = \\(x + 42\\over 7\\)<\/td> 6<\/td> 7<\/td> 8<\/td><\/tr> Points<\/td> A<\/td> B<\/td> C<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n x<\/td> 6<\/td> 12<\/td> 18<\/td><\/tr> y = \\(x – 6\\over 3\\)<\/td> 0<\/td> 2<\/td> 4<\/td><\/tr> Points<\/td> D<\/td> E<\/td> F<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n