{"id":10858,"date":"2022-06-03T17:02:24","date_gmt":"2022-06-03T11:32:24","guid":{"rendered":"https:\/\/mathemerize.com\/?p=10858"},"modified":"2022-06-03T17:02:28","modified_gmt":"2022-06-03T11:32:28","slug":"the-coach-of-a-cricket-team-buys-3-bats-and-6-balls-for-rs-3900-later-she-buys-another-bat-and-2-more-balls-of-the-same-kind-for-rs-1300","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-coach-of-a-cricket-team-buys-3-bats-and-6-balls-for-rs-3900-later-she-buys-another-bat-and-2-more-balls-of-the-same-kind-for-rs-1300\/","title":{"rendered":"The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300."},"content":{"rendered":"\n
Question<\/strong> : The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.<\/p>\n\n\n\n Solution<\/strong> : Let us denote the set of one bat by Rs x and one ball by Rs y. Then, the algebraic representation is given by the following equations :<\/p>\n\n\n\n 3x + 6y = 3900 …….(1)<\/p>\n\n\n\n and x + 2y = 1300 …..(2)<\/p>\n\n\n\n To obtain the equivalent geometric representation, we find two points on the line representing each equation. That is, we find two solutions of each equation.<\/p>\n\n\n\n These solutions are given below in the table.<\/p>\n\n\n\n For 3x + 6y = 3900<\/p>\n\n\n\n For x + 2y = 1300<\/p>\n\n\n\n We plot the points A(0, 650) and B(1300, 0) to obtain the geometric representation of 3x + 6y = 3900 and C(500, 400) and D(100, 600) to obtain the geometric representations of x + 2y = 1300.<\/p>\n\n\n\n We observe that these lines are coincident.<\/strong><\/p>\n\n\n\nx<\/td> 0<\/td> 1300<\/td><\/tr> y<\/td> 650<\/td> 0<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n x<\/td> 500<\/td> 100<\/td><\/tr> y<\/td> 400<\/td> 600<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n