{"id":10933,"date":"2022-06-08T14:52:43","date_gmt":"2022-06-08T09:22:43","guid":{"rendered":"https:\/\/mathemerize.com\/?p=10933"},"modified":"2022-06-08T14:52:46","modified_gmt":"2022-06-08T09:22:46","slug":"half-the-perimeter-of-rectangle-garden-whose-length-is-4m-more-than-its-width-is-36-cm-find-the-dimensions-of-the-garden","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/half-the-perimeter-of-rectangle-garden-whose-length-is-4m-more-than-its-width-is-36-cm-find-the-dimensions-of-the-garden\/","title":{"rendered":"Half the perimeter of rectangle garden, whose length is 4m more than its width, is 36 cm. Find the dimensions of the garden."},"content":{"rendered":"\n
Let x be the length of garden and y be its width.<\/p>\n\n\n\n
Then, <\/p>\n\n\n\n
According to question, perimeter = 2(length +width) = 2(x + y)<\/p>\n\n\n\n
Therefore, half perimeter = (x + y)<\/p>\n\n\n\n
But it is given as 36<\/p>\n\n\n\n
\\(\\therefore\\) (x + y) = 36<\/p>\n\n\n\n
Also, x = y + 4<\/p>\n\n\n\n
Now, we form the table given below for both the equations to find the solutions graphically.<\/p>\n\n\n\n
For equation, x + y = 36<\/p>\n\n\n\n
If x = 20, y =16<\/p>\n\n\n\n
If x = 24, y = 12<\/p>\n\n\n\n For equation, x – y = 4<\/p>\n\n\n\n If x = 10, y = 6<\/p>\n\n\n\n If x = 16, y = 12<\/p>\n\n\n\n Now plot the points in the table on the graph.<\/p>\n\n\n\n We see that lines intersect at point (20,16) as shown in the graph.<\/p>\n\n\n\n Hence, Length = 20 m and width = 16 m <\/strong><\/p>\n\n\n\nx<\/td> 20<\/td> 24<\/td><\/tr> y<\/td> 16<\/td> 12<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n x<\/td> 10<\/td> 16<\/td><\/tr> y<\/td> 6<\/td> 12<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n