{"id":11211,"date":"2022-06-27T14:38:13","date_gmt":"2022-06-27T09:08:13","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11211"},"modified":"2022-06-27T14:55:55","modified_gmt":"2022-06-27T09:25:55","slug":"the-ages-of-two-friends-ani-and-biju-differ-by-3-years-anis-father-dharam-is-twice-as-old-as-ani-and-biju-is-twice-as-old-as-his-sister-cathy-the-age-of-cathy-and-dharam-are-differ-by-30-years-fi","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-ages-of-two-friends-ani-and-biju-differ-by-3-years-anis-father-dharam-is-twice-as-old-as-ani-and-biju-is-twice-as-old-as-his-sister-cathy-the-age-of-cathy-and-dharam-are-differ-by-30-years-fi\/","title":{"rendered":"The ages of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The age of Cathy and Dharam are differ by 30 years. Find the ages of Ani and Biju."},"content":{"rendered":"

Solution<\/strong> :<\/h2>\n

Let x and y be the ages of Ani and Biju respectively. Then,<\/p>\n

According to Question,<\/p>\n

x + y = \\(\\pm 3\\)<\/p>\n

Dharam’s age = 2x,\u00a0 and\u00a0 Cathy’s age = \\(y\\over 2\\)<\/p>\n

Clearly, Dharam is older than Cathy.<\/p>\n

So, 2x – \\(y\\over 2\\) = 30<\/p>\n

\\(\\implies\\)\u00a0 4x – y = 60<\/p>\n

Thus, we have these two linear equations,<\/p>\n

x – y = 3\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0…….(1)<\/p>\n

4x – y = 60\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ……….(2)<\/p>\n

or\u00a0 \u00a0x – y = -3\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ……..(3)<\/p>\n

4x – y = 60\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 ……..(4)<\/p>\n

On Subtracting equation (2) from (1), we get<\/p>\n

-3x = -57\u00a0 \u00a0 \u00a0 \\(\\implies\\)\u00a0 \u00a0 x = 19<\/p>\n

Put the value of x = 19 in equation (1), we get<\/p>\n

19 – y = 3\u00a0 \u00a0\\(\\implies\\)\u00a0 \u00a0y = 16<\/p>\n

Now, On Subtracting equation (3) from (4), we get<\/p>\n

3x = 63\u00a0 \u00a0 \u00a0\\(\\implies\\)\u00a0 \u00a0 x = 21<\/p>\n

Put the value of x = 21 in equation (3), we get<\/p>\n

21 – y = – 3\u00a0 \u00a0 \u00a0\\(\\implies\\)\u00a0 \u00a0 \u00a0y = 24<\/p>\n

Hence, Ani’s age is 19 years<\/strong> and Biju’s is 16 years<\/strong><\/p>\n

or Ani’s age is 21 years<\/strong> and Biju’s age is 24 years<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : Let x and y be the ages of Ani and Biju respectively. Then, According to Question, x + y = \\(\\pm 3\\) Dharam’s age = 2x,\u00a0 and\u00a0 Cathy’s age = \\(y\\over 2\\) Clearly, Dharam is older than Cathy. So, 2x – \\(y\\over 2\\) = 30 \\(\\implies\\)\u00a0 4x – y = 60 Thus, we …<\/p>\n

The ages of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The age of Cathy and Dharam are differ by 30 years. Find the ages of Ani and Biju.<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[911,43],"tags":[],"yoast_head":"\nThe ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The age of Cathy and Dharam are differ by 30 years. Find the ages of Ani and Biju. - Mathemerize<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/the-ages-of-two-friends-ani-and-biju-differ-by-3-years-anis-father-dharam-is-twice-as-old-as-ani-and-biju-is-twice-as-old-as-his-sister-cathy-the-age-of-cathy-and-dharam-are-differ-by-30-years-fi\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The ages of two friends Ani and Biju differ by 3 years. Ani's father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The age of Cathy and Dharam are differ by 30 years. Find the ages of Ani and Biju. - Mathemerize\" \/>\n<meta property=\"og:description\" content=\"Solution : Let x and y be the ages of Ani and Biju respectively. Then, According to Question, x + y = (pm 3) Dharam’s age = 2x,\u00a0 and\u00a0 Cathy’s age = (yover 2) Clearly, Dharam is older than Cathy. So, 2x – (yover 2) = 30 (implies)\u00a0 4x – y = 60 Thus, we … The ages of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The age of Cathy and Dharam are differ by 30 years. Find the ages of Ani and Biju. 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Ani’s father Dharam is twice as old as Ani and Biju is twice as old as his sister Cathy. The age of Cathy and Dharam are differ by 30 years. Find the ages of Ani and Biju."}]},{"@type":"WebSite","@id":"https:\/\/mathemerize.com\/#website","url":"https:\/\/mathemerize.com\/","name":"Mathemerize","description":"Maths Tutorials - Study Math Online","publisher":{"@id":"https:\/\/mathemerize.com\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mathemerize.com\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Organization","@id":"https:\/\/mathemerize.com\/#organization","name":"Mathemerize","url":"https:\/\/mathemerize.com\/","logo":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/mathemerize.com\/#\/schema\/logo\/image\/","url":"https:\/\/i1.wp.com\/mathemerize.com\/wp-content\/uploads\/2021\/05\/logo.png?fit=140%2C96&ssl=1","contentUrl":"https:\/\/i1.wp.com\/mathemerize.com\/wp-content\/uploads\/2021\/05\/logo.png?fit=140%2C96&ssl=1","width":140,"height":96,"caption":"Mathemerize"},"image":{"@id":"https:\/\/mathemerize.com\/#\/schema\/logo\/image\/"},"sameAs":["https:\/\/www.instagram.com\/mathemerize\/"]},{"@type":"Person","@id":"https:\/\/mathemerize.com\/#\/schema\/person\/104c8bc54f90618130a6665299bc55df","name":"mathemerize","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/mathemerize.com\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/f0649d8b9c9f4ba7f1682b12d040d2a3?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/f0649d8b9c9f4ba7f1682b12d040d2a3?s=96&d=mm&r=g","caption":"mathemerize"},"sameAs":["https:\/\/mathemerize.com"],"url":"https:\/\/mathemerize.com\/author\/mathemerize\/"}]}},"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/posts\/11211"}],"collection":[{"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/comments?post=11211"}],"version-history":[{"count":3,"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/posts\/11211\/revisions"}],"predecessor-version":[{"id":11216,"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/posts\/11211\/revisions\/11216"}],"wp:attachment":[{"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/media?parent=11211"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/categories?post=11211"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mathemerize.com\/wp-json\/wp\/v2\/tags?post=11211"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}