{"id":11218,"date":"2022-06-28T14:40:45","date_gmt":"2022-06-28T09:10:45","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11218"},"modified":"2022-06-28T14:40:48","modified_gmt":"2022-06-28T09:10:48","slug":"one-says-give-me-a-hundred-friend-i-shall-then-become-twice-as-rich-as-you-the-other-replies-if-you-give-me-ten-i-shall-be-six-times-as-rich-as-you-tell-me-what-is-the-amount-of-their","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/one-says-give-me-a-hundred-friend-i-shall-then-become-twice-as-rich-as-you-the-other-replies-if-you-give-me-ten-i-shall-be-six-times-as-rich-as-you-tell-me-what-is-the-amount-of-their\/","title":{"rendered":"One says, “Give me a hundred, friend ! I shall then become twice as rich as you.” The other replies, “If you give me ten, I shall be six times as rich as you.” Tell me what is the amount of their (respectively) capital ?"},"content":{"rendered":"
Let two friends named as P and Q. Let P has Rs x and Q has Rs y.<\/p>\n
According to Question,<\/p>\n
x + 100 = 2(y – 100)<\/p>\n
\\(\\implies\\)\u00a0 x – 2y + 300 = 0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0………(1)<\/p>\n
y + 10 = 6(x – 10)<\/p>\n
\\(\\implies\\)\u00a0 6x – y – 70 = 0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0………(2)<\/p>\n
Multiply equation (2) by 2 and subtract from equation (1), we get<\/p>\n
-11x = -440\u00a0 \\(\\implies\\)\u00a0 x = 40<\/strong><\/p>\n Put the value of x = 40 in equation (1), we get<\/p>\n 40 – 3y + 300 = 0\u00a0 \u00a0 \\(\\implies\\)\u00a0 y = 70<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Solution : Let two friends named as P and Q. Let P has Rs x and Q has Rs y. According to Question, x + 100 = 2(y – 100) \\(\\implies\\)\u00a0 x – 2y + 300 = 0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0………(1) y + 10 = 6(x – 10) \\(\\implies\\)\u00a0 6x – y – …<\/p>\n