{"id":11250,"date":"2022-06-29T16:12:52","date_gmt":"2022-06-29T10:42:52","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11250"},"modified":"2022-06-29T16:12:56","modified_gmt":"2022-06-29T10:42:56","slug":"abcd-is-a-cyclic-quadrilateral-as-shown-in-figure-find-the-angles-of-the-cyclic-quadrilateral","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/abcd-is-a-cyclic-quadrilateral-as-shown-in-figure-find-the-angles-of-the-cyclic-quadrilateral\/","title":{"rendered":"ABCD is a cyclic quadrilateral as shown in figure. Find the angles of the cyclic quadrilateral."},"content":{"rendered":"
We know that the sum of opposite angles of cyclic quadrilateral is 180 degrees.<\/p>\n
Angles A and C, Angles B and D form pairs of opposite angles in the given cyclic quadrilateral ABCD.<\/p>\n
\\(\\angle\\)A + \\(\\angle\\)C = 180\u00a0 \u00a0and\u00a0 \\(\\angle\\)B + \\(\\angle\\)D = 180<\/p>\n
\\(\\implies\\)\u00a0 (4y + 20) + 4x = 180\u00a0 \u00a0and\u00a0 \u00a0(3y – 5) + (7x + 5) = 180<\/p>\n
\\(\\implies\\)\u00a0 4x + 4y – 160 = 0\u00a0 \u00a0 \u00a0\\(\\implies\\) x + y – 40 = 0\u00a0 \u00a0 \u00a0 …………(1)<\/p>\n
and\u00a0 7x + 3y – 180 = 0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0…………(2)<\/p>\n
Multiplying equation (1) by and subtracting from equation (2), we get<\/p>\n
4x – 60 = 0\u00a0 \u00a0 \u00a0 \\(\\implies\\)\u00a0 \u00a0 x = 15<\/p>\n
Put the value of x = 15 in equation (1), we get<\/p>\n
15 + y – 40 = 0\u00a0 \u00a0 \u00a0\\(\\implies\\)\u00a0 \u00a0y = 25<\/p>\n
Hence, \\(\\angle\\)A = 4y + 20 = 120 degrees<\/strong><\/p>\n \\(\\angle\\)B = 3y – 5 = 70 degrees<\/strong><\/p>\n \\(\\angle\\)C = 4x = 60 degrees<\/strong><\/p>\n \\(\\angle\\)D = 7x + 5 = 110 degrees<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Solution : We know that the sum of opposite angles of cyclic quadrilateral is 180 degrees. Angles A and C, Angles B and D form pairs of opposite angles in the given cyclic quadrilateral ABCD. \\(\\angle\\)A + \\(\\angle\\)C = 180\u00a0 \u00a0and\u00a0 \\(\\angle\\)B + \\(\\angle\\)D = 180 \\(\\implies\\)\u00a0 (4y + 20) + 4x = 180\u00a0 \u00a0and\u00a0 …<\/p>\n