{"id":11280,"date":"2022-07-01T00:54:19","date_gmt":"2022-06-30T19:24:19","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11280"},"modified":"2022-07-01T00:55:16","modified_gmt":"2022-06-30T19:25:16","slug":"in-the-figure-if-lm-cb-and-ln-cd-prove-that-amover-ab-anover-ad","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/in-the-figure-if-lm-cb-and-ln-cd-prove-that-amover-ab-anover-ad\/","title":{"rendered":"In the figure, if LM || CB and LN || CD, prove that \\(AM\\over AB\\) = \\(AN\\over AD\\)."},"content":{"rendered":"

Solution :<\/h2>\n

In triangle ABC,\"image\"<\/p>\n

Given,\u00a0 \u00a0 \u00a0 \u00a0 LM || CB<\/p>\n

By Basic proportionality theorem, we have<\/p>\n

\\(AM\\over AB\\) = \\(AL\\over AC\\)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0……..(1)<\/p>\n

In triangle ACD,<\/p>\n

Given,\u00a0 \u00a0 \u00a0 \u00a0 LN || CD<\/p>\n

By Basic proportionality theorem, we have<\/p>\n

\\(AL\\over AC\\) = \\(AN\\over AD\\)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0……..(2)<\/p>\n

From (1) and (2), we obtain that<\/p>\n

\\(AM\\over AB\\) = \\(AN\\over AD\\)<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

Solution : In triangle ABC, Given,\u00a0 \u00a0 \u00a0 \u00a0 LM || CB By Basic proportionality theorem, we have \\(AM\\over AB\\) = \\(AL\\over AC\\)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0……..(1) In triangle ACD, Given,\u00a0 \u00a0 \u00a0 \u00a0 LN || CD By Basic proportionality theorem, we have \\(AL\\over AC\\) = \\(AN\\over AD\\)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0……..(2) From …<\/p>\n

In the figure, if LM || CB and LN || CD, prove that \\(AM\\over AB\\) = \\(AN\\over AD\\).<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,912],"tags":[],"yoast_head":"\nIn the figure, if LM || CB and LN || CD, prove that \\(AM\\over AB\\) = \\(AN\\over AD\\). - Mathemerize<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/in-the-figure-if-lm-cb-and-ln-cd-prove-that-amover-ab-anover-ad\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"In the figure, if LM || CB and LN || CD, prove that \\(AM\\over AB\\) = \\(AN\\over AD\\). - Mathemerize\" \/>\n<meta property=\"og:description\" content=\"Solution : In triangle ABC, Given,\u00a0 \u00a0 \u00a0 \u00a0 LM || CB By Basic proportionality theorem, we have (AMover AB) = (ALover AC)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0……..(1) In triangle ACD, Given,\u00a0 \u00a0 \u00a0 \u00a0 LN || CD By Basic proportionality theorem, we have (ALover AC) = (ANover AD)\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0……..(2) From … In the figure, if LM || CB and LN || CD, prove that (AMover AB) = (ANover AD). 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