{"id":11299,"date":"2022-07-01T01:35:07","date_gmt":"2022-06-30T20:05:07","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11299"},"modified":"2022-07-01T01:35:10","modified_gmt":"2022-06-30T20:05:10","slug":"prove-that-the-line-joining-the-mid-points-of-two-sides-of-a-triangle-is-parallel-to-the-third-side","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/prove-that-the-line-joining-the-mid-points-of-two-sides-of-a-triangle-is-parallel-to-the-third-side\/","title":{"rendered":"Prove that the line joining the mid-points of two sides of a triangle is parallel to the third side."},"content":{"rendered":"
Given<\/strong> : A triangle ABC in which D and E are mid point of sides AB and AC respectively.<\/p>\n To Prove<\/strong> :\u00a0 DE || BC<\/p>\n Proof<\/strong> : Since sides AB and AC have D and E as mid points,<\/p>\n \\(\\therefore\\)\u00a0 \u00a0AD = DB\u00a0 and\u00a0 AE = EC<\/p>\n \\(\\implies\\)\u00a0 \\(AD\\over DB\\) = 1\u00a0 and\u00a0 \\(AE\\over EC\\) = 1<\/p>\n \\(\\implies\\)\u00a0 \\(AD\\over DB\\) = \\(AE\\over EC\\)<\/p>\n Hence, By converse of Basic proportionality theorem,<\/p>\n DE || BC.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Solution : Given : A triangle ABC in which D and E are mid point of sides AB and AC respectively. To Prove :\u00a0 DE || BC Proof : Since sides AB and AC have D and E as mid points, \\(\\therefore\\)\u00a0 \u00a0AD = DB\u00a0 and\u00a0 AE = EC \\(\\implies\\)\u00a0 \\(AD\\over DB\\) = 1\u00a0 and\u00a0 …<\/p>\n