{"id":11342,"date":"2022-07-07T20:07:21","date_gmt":"2022-07-07T14:37:21","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11342"},"modified":"2022-07-07T20:07:25","modified_gmt":"2022-07-07T14:37:25","slug":"s-and-t-are-points-on-sides-pr-and-qr-of-triangle-pqr-such-that-angle-p-angle-rts-show-that-triangle-rpq-triangle-rts","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/s-and-t-are-points-on-sides-pr-and-qr-of-triangle-pqr-such-that-angle-p-angle-rts-show-that-triangle-rpq-triangle-rts\/","title":{"rendered":"S and T are points on sides PR and QR of triangle PQR such that \\(\\angle\\) P = \\(\\angle\\) RTS. Show that \\(\\triangle\\) RPQ ~ \\(\\triangle\\) RTS."},"content":{"rendered":"
Given<\/strong> : \\(\\triangle\\) RPQ and \\(\\triangle\\) RTS where \\(\\angle\\) P = \\(\\angle\\) RTS<\/p>\n To prove<\/strong> : \\(\\triangle\\) RPQ ~ \\(\\triangle\\) RTS<\/p>\n Proof<\/strong> : In \\(\\triangle\\) RPQ and \\(\\triangle\\) RTS<\/p>\n Given,\u00a0 \u00a0 \\(\\angle\\) P = \\(\\angle\\) RTS<\/p>\n \\(\\angle\\) R = \\(\\angle\\) R\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (common)<\/p>\n Hence, By AA similarity, \\(\\triangle\\) RPQ ~ \\(\\triangle\\) RTS<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Solution : Given : \\(\\triangle\\) RPQ and \\(\\triangle\\) RTS where \\(\\angle\\) P = \\(\\angle\\) RTS To prove : \\(\\triangle\\) RPQ ~ \\(\\triangle\\) RTS Proof : In \\(\\triangle\\) RPQ and \\(\\triangle\\) RTS Given,\u00a0 \u00a0 \\(\\angle\\) P = \\(\\angle\\) RTS \\(\\angle\\) R = \\(\\angle\\) R\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (common) Hence, By AA similarity, …<\/p>\n