{"id":11448,"date":"2022-07-11T16:06:47","date_gmt":"2022-07-11T10:36:47","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11448"},"modified":"2022-07-11T16:06:50","modified_gmt":"2022-07-11T10:36:50","slug":"sides-of-some-triangles-are-given-below-determine-which-of-them-are-right-triangles-in-case-of-a-right-triangle-write-the-length-of-its-hypotenuse-i-7-cm-24-cm-25-cm-ii-3-cm-8-cm-6-c","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/sides-of-some-triangles-are-given-below-determine-which-of-them-are-right-triangles-in-case-of-a-right-triangle-write-the-length-of-its-hypotenuse-i-7-cm-24-cm-25-cm-ii-3-cm-8-cm-6-c\/","title":{"rendered":"Sides of some triangles are given below. Determine which of them are right triangles. In case of a right triangle, write the length of its hypotenuse (i) 7 cm, 24 cm, 25 cm (ii) 3 cm, 8 cm, 6 cm (iii) 50 cm, 80 cm, 100 cm (iv) 13 cm, 12 cm, 5 cm"},"content":{"rendered":"
(i)<\/strong> 7 cm, 24 cm, 25 cm<\/p>\n Let AB = 7 cm, BC = 24 cm, CA = 25 cm<\/p>\n then\u00a0 \\({AB}^2\\) = 49,\u00a0 \\({BC}^2\\) = 576\u00a0 and\u00a0 \\({CA}^2\\) = 625<\/p>\n \\({AB}^2\\) + \\({BC}^2\\) = 625 = \\({CA}^2\\)<\/p>\n Yes, ABC is a right triangle<\/strong> and its hypotenuse is 25 cm.<\/strong><\/p>\n (ii)<\/strong> 3 cm, 8 cm, 6 cm<\/p>\n Let AB = 3 cm, BC = 8 cm, CA = 6 cm<\/p>\n then\u00a0 \\({AB}^2\\) = 9,\u00a0 \\({BC}^2\\) = 64\u00a0 and\u00a0 \\({CA}^2\\) = 36<\/p>\n \\({AB}^2\\) + \\({CA}^2\\) = 45 \\(\\ne\\) \\({BC}^2\\)<\/p>\n No, ABC is not a right triangle.<\/strong><\/p>\n (iii)<\/strong> 50 cm, 80 cm, 100 cm<\/p>\n Let AB =\u00a0 50 cm, BC = 80 cm, CA = 100 cm<\/p>\n then\u00a0 \\({AB}^2\\) = 2500,\u00a0 \\({BC}^2\\) = 6400\u00a0 and\u00a0 \\({CA}^2\\) = 10000<\/p>\n \\({AB}^2\\) + \\({BC}^2\\) = 8900 \\(\\ne\\) \\({CA}^2\\)<\/p>\n No, ABC is not a right triangle.<\/strong><\/p>\n (iv)<\/strong> 13 cm, 12 cm, 5 cm<\/p>\n Let AB = 13 cm, BC = 12 cm, CA = 5 cm<\/p>\n then\u00a0 \\({AB}^2\\) = 169,\u00a0 \\({BC}^2\\) = 144\u00a0 and\u00a0 \\({CA}^2\\) = 25<\/p>\n \\({BC}^2\\) + \\({CA}^2\\) = 169 = \\({AB}^2\\)<\/p>\n Yes, ABC is a\u00a0right triangle<\/strong> and its hypotenuse is 13\u00a0cm.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Solution : (i) 7 cm, 24 cm, 25 cm Let AB = 7 cm, BC = 24 cm, CA = 25 cm then\u00a0 \\({AB}^2\\) = 49,\u00a0 \\({BC}^2\\) = 576\u00a0 and\u00a0 \\({CA}^2\\) = 625 \\({AB}^2\\) + \\({BC}^2\\) = 625 = \\({CA}^2\\) Yes, ABC is a right triangle and its hypotenuse is 25 cm. (ii) 3 cm, …<\/p>\n