{"id":11450,"date":"2022-07-11T16:39:02","date_gmt":"2022-07-11T11:09:02","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11450"},"modified":"2022-07-11T16:39:07","modified_gmt":"2022-07-11T11:09:07","slug":"pqr-is-a-triangle-right-angled-at-p-and-m-is-a-point-on-qr-such-that-pm-perp-qr-show-that-pm2-qm-mr","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/pqr-is-a-triangle-right-angled-at-p-and-m-is-a-point-on-qr-such-that-pm-perp-qr-show-that-pm2-qm-mr\/","title":{"rendered":"PQR is a triangle right angled at P and M is a point on QR such that PM \\(\\perp\\) QR. Show that \\({PM}^2\\) = QM.MR."},"content":{"rendered":"
Since, PM \\(\\perp\\) QR, therefore,<\/p>\n
\\(\\triangle\\) PQM ~ \\(\\triangle\\) RPM<\/p>\n
\\(\\implies\\)\u00a0 \\(PM\\over QM\\) = \\(MR\\over PM\\)<\/p>\n
So, \\({PM}^2\\) = QM.MR<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Solution : Since, PM \\(\\perp\\) QR, therefore, \\(\\triangle\\) PQM ~ \\(\\triangle\\) RPM \\(\\implies\\)\u00a0 \\(PM\\over QM\\) = \\(MR\\over PM\\) So, \\({PM}^2\\) = QM.MR.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,912],"tags":[],"yoast_head":"\n