{"id":11482,"date":"2022-07-12T12:58:11","date_gmt":"2022-07-12T07:28:11","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11482"},"modified":"2022-07-12T12:58:15","modified_gmt":"2022-07-12T07:28:15","slug":"a-ladder-10-m-long-reaches-a-window-8-m-above-the-ground-find-the-distance-of-the-foot-of-the-ladder-from-the-base-of-the-wall","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/a-ladder-10-m-long-reaches-a-window-8-m-above-the-ground-find-the-distance-of-the-foot-of-the-ladder-from-the-base-of-the-wall\/","title":{"rendered":"A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall."},"content":{"rendered":"<h2>Solution :<\/h2>\n<p>Let ladder be AB, B be the window and CB be the wall. Then, ABC is a right triangle, angled at C.<img decoding=\"async\" loading=\"lazy\" class=\" wp-image-11495 alignright\" src=\"https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/07\/similartriangles6-5-9.jpeg?resize=137%2C149&#038;ssl=1\" alt=\"triangle\" width=\"137\" height=\"149\" srcset=\"https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/07\/similartriangles6-5-9.jpeg?resize=277%2C300&amp;ssl=1 277w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/07\/similartriangles6-5-9.jpeg?resize=944%2C1024&amp;ssl=1 944w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/07\/similartriangles6-5-9.jpeg?resize=768%2C833&amp;ssl=1 768w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/07\/similartriangles6-5-9.jpeg?resize=1416%2C1536&amp;ssl=1 1416w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/07\/similartriangles6-5-9.jpeg?w=1700&amp;ssl=1 1700w\" sizes=\"(max-width: 137px) 100vw, 137px\" data-recalc-dims=\"1\" \/><\/p>\n<p>\\(\\therefore\\)\u00a0 \\({AB}^2\\) = \\({AC}^2\\) + \\({BC}^2\\)<\/p>\n<p>So,\u00a0 \\({10}^2\\) = \\({AC}^2\\) + \\(8^2\\)<\/p>\n<p>or\u00a0 \\({AC}^2\\) = 100 &#8211; 64<\/p>\n<p>\\(\\implies\\) \\({AC}^2\\) = 36<\/p>\n<p>\\(\\implies\\)\u00a0 AC = 6 m<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Solution : Let ladder be AB, B be the window and CB be the wall. Then, ABC is a right triangle, angled at C. \\(\\therefore\\)\u00a0 \\({AB}^2\\) = \\({AC}^2\\) + \\({BC}^2\\) So,\u00a0 \\({10}^2\\) = \\({AC}^2\\) + \\(8^2\\) or\u00a0 \\({AC}^2\\) = 100 &#8211; 64 \\(\\implies\\) \\({AC}^2\\) = 36 \\(\\implies\\)\u00a0 AC = 6 m<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,912],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A ladder 10 m long reaches a window 8 m above the ground. 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