{"id":11630,"date":"2022-08-03T20:37:14","date_gmt":"2022-08-03T15:07:14","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11630"},"modified":"2022-08-03T20:37:22","modified_gmt":"2022-08-03T15:07:22","slug":"given-15-cot-a-8-find-sin-a-and-sec-a","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/given-15-cot-a-8-find-sin-a-and-sec-a\/","title":{"rendered":"Given 15 cot A = 8, find sin A and sec A."},"content":{"rendered":"<h2>Solution :<\/h2>\n<p>We have,<img decoding=\"async\" loading=\"lazy\" class=\" wp-image-11636 alignright\" src=\"https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/08\/trigonometry8-1-4.jpeg?resize=168%2C267&#038;ssl=1\" alt=\"triangle\" width=\"168\" height=\"267\" srcset=\"https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/08\/trigonometry8-1-4.jpeg?resize=189%2C300&amp;ssl=1 189w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/08\/trigonometry8-1-4.jpeg?resize=646%2C1024&amp;ssl=1 646w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/08\/trigonometry8-1-4.jpeg?resize=768%2C1218&amp;ssl=1 768w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/08\/trigonometry8-1-4.jpeg?resize=968%2C1536&amp;ssl=1 968w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/08\/trigonometry8-1-4.jpeg?resize=1291%2C2048&amp;ssl=1 1291w, https:\/\/i0.wp.com\/mathemerize.com\/wp-content\/uploads\/2022\/08\/trigonometry8-1-4.jpeg?w=1387&amp;ssl=1 1387w\" sizes=\"(max-width: 168px) 100vw, 168px\" data-recalc-dims=\"1\" \/><\/p>\n<p>15 cot A = 8\u00a0 \\(\\implies\\)\u00a0 cot A = \\(8\\over 15\\)<\/p>\n<p>Draw a right triangle ABC,<\/p>\n<p>cot A = \\(AB\\over BC\\) = \\(8\\over 15\\)<\/p>\n<p>If BC = 15k, then AB = 8k, where k is any positive number.<\/p>\n<p>By using Pythagoras Theorem,<\/p>\n<p>\\({AC}^2\\) = \\({AB}^2\\) + \\({BC}^2\\)<\/p>\n<p>= \\(64k^2\\) + \\(225k^2\\) = \\(289k^2\\)<\/p>\n<p>\\(\\implies\\)\u00a0 AC = 17k<\/p>\n<p>Thus, sin\u00a0 A = \\(BC\\over AC\\) = \\(15k\\over 17k\\) = <strong>\\(15\\over 17\\)<\/strong><\/p>\n<p>sec A = \\(AC\\over AB\\) = \\(!7k\\over 8k\\) = <strong>\\(17\\over 8\\)<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Solution : We have, 15 cot A = 8\u00a0 \\(\\implies\\)\u00a0 cot A = \\(8\\over 15\\) Draw a right triangle ABC, cot A = \\(AB\\over BC\\) = \\(8\\over 15\\) If BC = 15k, then AB = 8k, where k is any positive number. By using Pythagoras Theorem, \\({AC}^2\\) = \\({AB}^2\\) + \\({BC}^2\\) = \\(64k^2\\) + \\(225k^2\\) &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/mathemerize.com\/given-15-cot-a-8-find-sin-a-and-sec-a\/\"> <span class=\"screen-reader-text\">Given 15 cot A = 8, find sin A and sec A.<\/span> Read More &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,60],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v20.12 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Given 15 cot A = 8, find sin A and sec A. - Mathemerize<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mathemerize.com\/given-15-cot-a-8-find-sin-a-and-sec-a\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Given 15 cot A = 8, find sin A and sec A. - Mathemerize\" \/>\n<meta property=\"og:description\" content=\"Solution : We have, 15 cot A = 8\u00a0 (implies)\u00a0 cot A = (8over 15) Draw a right triangle ABC, cot A = (ABover BC) = (8over 15) If BC = 15k, then AB = 8k, where k is any positive number. 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Mathemerize","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mathemerize.com\/given-15-cot-a-8-find-sin-a-and-sec-a\/","og_locale":"en_US","og_type":"article","og_title":"Given 15 cot A = 8, find sin A and sec A. - Mathemerize","og_description":"Solution : We have, 15 cot A = 8\u00a0 (implies)\u00a0 cot A = (8over 15) Draw a right triangle ABC, cot A = (ABover BC) = (8over 15) If BC = 15k, then AB = 8k, where k is any positive number. By using Pythagoras Theorem, ({AC}^2) = ({AB}^2) + ({BC}^2) = (64k^2) + (225k^2) &hellip; Given 15 cot A = 8, find sin A and sec A. 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