{"id":11705,"date":"2022-08-14T23:49:02","date_gmt":"2022-08-14T18:19:02","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11705"},"modified":"2022-08-14T23:49:09","modified_gmt":"2022-08-14T18:19:09","slug":"if-tan-a-b-sqrt3-and-tan-a-b-1over-sqrt3-0-a-b-le-90-a-ge-b-find-a-and-b","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/if-tan-a-b-sqrt3-and-tan-a-b-1over-sqrt3-0-a-b-le-90-a-ge-b-find-a-and-b\/","title":{"rendered":"If tan (A + B) = \\(\\sqrt{3}\\) and tan (A – B) = \\(1\\over \\sqrt{3}\\) ; 0 < A + B \\(\\le\\) 90 ; A \\(\\ge\\) B, find A and B."},"content":{"rendered":"
We have, tan (A + B) = \\(\\sqrt{3}\\)<\/p>\n
\\(\\implies\\)\u00a0 tan (A + B) = tan 60 \\(\\implies\\)\u00a0 A + B = 60\u00a0 \u00a0 \u00a0 \u00a0 \u00a0…………(1)<\/p>\n
Also, tan (A – B) = \\(1\\over \\sqrt{3}\\)<\/p>\n
\\(\\implies\\)\u00a0 tan(A – B) = tan 30 \\(\\implies\\)\u00a0 A – B = 30\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 …………(2)<\/p>\n
Solving (1) and (2), we get<\/p>\n
A = 45 and B = 15<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Solution : We have, tan (A + B) = \\(\\sqrt{3}\\) \\(\\implies\\)\u00a0 tan (A + B) = tan 60 \\(\\implies\\)\u00a0 A + B = 60\u00a0 \u00a0 \u00a0 \u00a0 \u00a0…………(1) Also, tan (A – B) = \\(1\\over \\sqrt{3}\\) \\(\\implies\\)\u00a0 tan(A – B) = tan 30 \\(\\implies\\)\u00a0 A – B = 30\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 …………(2) …<\/p>\n