{"id":11712,"date":"2022-08-16T00:50:50","date_gmt":"2022-08-15T19:20:50","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11712"},"modified":"2022-08-16T00:50:57","modified_gmt":"2022-08-15T19:20:57","slug":"evaluate-the-following","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/evaluate-the-following\/","title":{"rendered":"Evaluate the following :"},"content":{"rendered":"
(i)<\/strong>\u00a0 \\(sin 18\\over cos 72\\)<\/p>\n (ii)<\/strong>\u00a0 \\(tan 26\\over cot 64\\)<\/p>\n (iii)<\/strong>\u00a0 cos 48 – sin 42<\/p>\n (iv)<\/strong>\u00a0 cosec 31 – sec 59<\/p>\n (i)<\/strong>\u00a0 \\(sin 18\\over cos 72\\) = \\(sin 18\\over cos (90 – 18)\\) = \\(sin 18\\over sin 18\\) = 1<\/strong><\/p>\n (ii)<\/strong>\u00a0 \\(tan 26\\over cot 64\\) = \\(tan 26\\over cot (90 – 26)\\) = \\(tan 26\\over tan 26\\) = 1<\/strong><\/p>\n (iii)<\/strong>\u00a0 cos 48 – sin 42 = cos(90 – 42) – sin 42 = sin 42 – sin 42 = 0<\/strong><\/p>\n (iv)<\/strong>\u00a0 cosec 31 – sec 59 = cosec 31 – sec(90 – 31) = cosec 31 – cosec 31 = 0<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Question : (i)\u00a0 \\(sin 18\\over cos 72\\) (ii)\u00a0 \\(tan 26\\over cot 64\\) (iii)\u00a0 cos 48 – sin 42 (iv)\u00a0 cosec 31 – sec 59 Solution : (i)\u00a0 \\(sin 18\\over cos 72\\) = \\(sin 18\\over cos (90 – 18)\\) = \\(sin 18\\over sin 18\\) = 1 (ii)\u00a0 \\(tan 26\\over cot 64\\) = \\(tan 26\\over cot (90 …<\/p>\nSolution :<\/h2>\n