{"id":11714,"date":"2022-08-16T00:58:05","date_gmt":"2022-08-15T19:28:05","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11714"},"modified":"2022-08-16T00:58:12","modified_gmt":"2022-08-15T19:28:12","slug":"show-that-i-tan-48-tan-23-tan-42-tan-67-1-ii-cos-38-cos-52-sin-38-sin-52-0","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/show-that-i-tan-48-tan-23-tan-42-tan-67-1-ii-cos-38-cos-52-sin-38-sin-52-0\/","title":{"rendered":"Show that : (i) tan 48 tan 23 tan 42 tan 67 = 1 (ii) cos 38 cos 52 – sin 38 sin 52 = 0"},"content":{"rendered":"
(i)<\/strong>\u00a0 L.H.S = tan 48 tan 23 tan 42 tan 67 = \\(1\\over cot 48\\). tan 23 tan 42 \\(1\\over cot 67\\)<\/p>\n = \\(1\\over cot (90 – 42)\\). tan 23 tan 42 \\(1\\over cot (90 – 23)\\) = \\(1\\over tan 42\\). tan 23 tan 42 \\(1\\over tan 23\\)<\/p>\n = 1 = R.H.S.<\/strong><\/p>\n (ii)<\/strong>\u00a0 L.H.S = cos 38 cos 52 – sin 38 sin 52 = cos 38.cos(90 – 38) – sin 38 sin(90 – 38)<\/p>\n = cos 38 sin 38 – sin 38 cos 38 = 0 = R.H.S.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Solution : (i)\u00a0 L.H.S = tan 48 tan 23 tan 42 tan 67 = \\(1\\over cot 48\\). tan 23 tan 42 \\(1\\over cot 67\\) = \\(1\\over cot (90 – 42)\\). tan 23 tan 42 \\(1\\over cot (90 – 23)\\) = \\(1\\over tan 42\\). tan 23 tan 42 \\(1\\over tan 23\\) = 1 = R.H.S. (ii)\u00a0 …<\/p>\n