{"id":11724,"date":"2022-08-16T17:19:50","date_gmt":"2022-08-16T11:49:50","guid":{"rendered":"https:\/\/mathemerize.com\/?p=11724"},"modified":"2022-08-16T17:19:56","modified_gmt":"2022-08-16T11:49:56","slug":"if-a-b-and-c-are-the-interior-angles-of-a-triangle-abc-show-that-sinbcover-2-cosaover-2","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/if-a-b-and-c-are-the-interior-angles-of-a-triangle-abc-show-that-sinbcover-2-cosaover-2\/","title":{"rendered":"If A, B and C are the interior angles of a triangle ABC, show that sin\\(B+C\\over 2\\) = cos\\(A\\over 2\\)."},"content":{"rendered":"
Since A, B and C are the interior angles of a triangle ABC<\/p>\n
\\(\\therefore\\)\u00a0 \u00a0A + B + C = 180<\/p>\n
\\(\\implies\\)\u00a0 \\(A\\over 2\\) + \\(B\\over 2\\) + \\(C\\over 2\\) = 90<\/p>\n
\\(\\implies\\)\u00a0 \\(B\\over 2\\) + \\(C\\over 2\\) = 90 – \\(A\\over 2\\)<\/p>\n
\\(\\implies\\)\u00a0 sin(\\(B+C\\over 2\\)) = sin(90 – \\(A\\over 2\\))<\/p>\n
\\(\\implies\\)\u00a0 \u00a0sin\\(B+C\\over 2\\) = cos\\(A\\over 2\\).<\/p>\n","protected":false},"excerpt":{"rendered":"
Solution : Since A, B and C are the interior angles of a triangle ABC \\(\\therefore\\)\u00a0 \u00a0A + B + C = 180 \\(\\implies\\)\u00a0 \\(A\\over 2\\) + \\(B\\over 2\\) + \\(C\\over 2\\) = 90 \\(\\implies\\)\u00a0 \\(B\\over 2\\) + \\(C\\over 2\\) = 90 – \\(A\\over 2\\) \\(\\implies\\)\u00a0 sin(\\(B+C\\over 2\\)) = sin(90 – \\(A\\over 2\\)) \\(\\implies\\)\u00a0 \u00a0sin\\(B+C\\over …<\/p>\n