{"id":12033,"date":"2022-09-11T12:35:42","date_gmt":"2022-09-11T07:05:42","guid":{"rendered":"https:\/\/mathemerize.com\/?p=12033"},"modified":"2022-09-11T12:35:47","modified_gmt":"2022-09-11T07:05:47","slug":"the-following-distribution-shows-the-daily-pocket-allowance-of-children-of-a-locality-the-mean-pocket-allowance-is-18-rupees-find-the-missing-frequency-f","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-following-distribution-shows-the-daily-pocket-allowance-of-children-of-a-locality-the-mean-pocket-allowance-is-18-rupees-find-the-missing-frequency-f\/","title":{"rendered":"The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is 18 rupees. Find the missing frequency f."},"content":{"rendered":"\n

Question :<\/h2>\n\n\n\n
Class Interval<\/td>11 – 13<\/td>13 – 15<\/td>15 – 17<\/td>17 – 19<\/td>19 – 21<\/td>21 – 23<\/td>23 – 25<\/td><\/tr>
Frequency<\/td>7<\/td>6<\/td>9<\/td>13<\/td>f<\/td>5<\/td>4<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

Solution :<\/h2>\n\n\n\n

We have,<\/p>\n\n\n\n

Class Interval<\/td>Mid-value (\\(x_i\\))<\/td>Frequency (\\(f_i\\))<\/td>\\(f_ix_i\\)<\/td><\/tr>
11 – 13<\/td>12<\/td>7<\/td>84<\/td><\/tr>
13 – 15<\/td>14<\/td>6<\/td>84<\/td><\/tr>
15 – 17<\/td>16<\/td>9<\/td>144<\/td><\/tr>
17 – 19<\/td>18<\/td>13<\/td>234<\/td><\/tr>
19 – 21<\/td>20<\/td>f<\/td>20 f<\/td><\/tr>
21 – 23<\/td>22<\/td>5<\/td>110<\/td><\/tr>
23 – 25<\/td>24<\/td>4<\/td>90<\/td><\/tr>
<\/td><\/td>\\(\\sum f_i\\) = 44 + f<\/td>\\(\\sum f_ix_i\\) = 752 + 20f<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

So, Mean (\\(\\bar{x}\\)) = \\(\\sum f_ix_i\\over f_i\\) = \\(752 + 20f\\over 44 + f\\)<\/p>\n\n\n\n

\\(\\implies\\) 18 = \\(752 + 20f\\over 44 + f\\)<\/p>\n\n\n\n

\\(\\implies\\) 752 + 20f = 792 + 18f<\/p>\n\n\n\n

\\(\\implies\\) 2f = 40<\/p>\n\n\n\n

\\(\\implies\\) f = 20<\/p>\n\n\n\n

Hence, the missing frequency is 20<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"

Question : Class Interval 11 – 13 13 – 15 15 – 17 17 – 19 19 – 21 21 – 23 23 – 25 Frequency 7 6 9 13 f 5 4 Solution : We have, Class Interval Mid-value (\\(x_i\\)) Frequency (\\(f_i\\)) \\(f_ix_i\\) 11 – 13 12 7 84 13 – 15 14 6 …<\/p>\n

The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is 18 rupees. Find the missing frequency f.<\/span> Read More »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-global-header-display":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":""},"categories":[43,58],"tags":[],"yoast_head":"\nThe following distribution shows the daily pocket allowance of children of a locality. 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