{"id":12083,"date":"2022-09-14T23:35:19","date_gmt":"2022-09-14T18:05:19","guid":{"rendered":"https:\/\/mathemerize.com\/?p=12083"},"modified":"2022-09-14T23:36:09","modified_gmt":"2022-09-14T18:06:09","slug":"the-table-below-shows-expenditure-on-food-of-25-households-in-a-locality-find-the-mean-daily-expenditure-on-food-by-a-suitable-method","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/the-table-below-shows-expenditure-on-food-of-25-households-in-a-locality-find-the-mean-daily-expenditure-on-food-by-a-suitable-method\/","title":{"rendered":"The table below shows expenditure on food of 25 households in a locality. Find the mean daily expenditure on food by a suitable method."},"content":{"rendered":"\n
Daily expenditure (in Rupees)<\/td> | 100 – 150<\/td> | 150 – 200<\/td> | 200 – 250<\/td> | 250 – 300<\/td> | 300 – 350<\/td><\/tr> | |||||||||||||||||||||||||||||||||||
Number of households<\/td> | 4<\/td> | 5<\/td> | 12<\/td> | 2<\/td> | 2<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\nSolution :<\/h2>\n\n\n\nLet the assumed mean, A = 225, class size, h = 50<\/p>\n\n\n\n So, \\(u_i\\) = \\(x_i – A\\over h\\) = \\(x_i – 225\\over 50\\)<\/p>\n\n\n\n So, Mean = A + h\\(\\sum f_iu_i\\over \\sum f_i\\) = 225 + 50 \\(\\times\\) \\(-7\\over 25\\) = 225 – 14 = 211<\/p>\n\n\n\n Hence, the mean daily expenditure on food is 211 rupees<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Question : Daily expenditure (in Rupees) 100 – 150 150 – 200 200 – 250 250 – 300 300 – 350 Number of households 4 5 12 2 2 Solution : Let the assumed mean, A = 225, class size, h = 50 So, \\(u_i\\) = \\(x_i – A\\over h\\) = \\(x_i – 225\\over 50\\) …<\/p>\n |