{"id":12103,"date":"2022-09-15T23:49:24","date_gmt":"2022-09-15T18:19:24","guid":{"rendered":"https:\/\/mathemerize.com\/?p=12103"},"modified":"2022-09-15T23:49:27","modified_gmt":"2022-09-15T18:19:27","slug":"to-find-out-concentration-of-so_2-in-the-air-in-parts-per-million-i-e-ppm-the-data-was-collected-for-30-localities-in-a-certain-city-and-is-presented-below-find-the-mean-concentration-of","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/to-find-out-concentration-of-so_2-in-the-air-in-parts-per-million-i-e-ppm-the-data-was-collected-for-30-localities-in-a-certain-city-and-is-presented-below-find-the-mean-concentration-of\/","title":{"rendered":"To find out concentration of \\(SO_2\\) in the air (in parts per million, i.e. ppm), the data was collected for 30 localities in a certain city and is presented below. Find the mean concentration of \\(SO_2\\) in the air."},"content":{"rendered":"\n
Concentration of \\(SO_2\\) (in ppm)<\/td> | Frequency<\/td><\/tr> | ||||||||||||||||||||||||||||||||||||||||
0.00 – 0.04<\/td> | 4<\/td><\/tr> | ||||||||||||||||||||||||||||||||||||||||
0.04 – 0.08<\/td> | 9<\/td><\/tr> | ||||||||||||||||||||||||||||||||||||||||
0.08 – 0.12<\/td> | 9<\/td><\/tr> | ||||||||||||||||||||||||||||||||||||||||
0.12 – 0.16<\/td> | 2<\/td><\/tr> | ||||||||||||||||||||||||||||||||||||||||
0.16 – 0.20<\/td> | 4<\/td><\/tr> | ||||||||||||||||||||||||||||||||||||||||
0.20 – 0.24<\/td> | 2<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\nSolution : <\/h2>\n\n\n\nLet the assumed mean a = 0.10<\/p>\n\n\n\n By step deviation method :<\/p>\n\n\n\n Mean = a + \\(\\sum f_iu_i\\over \\sum f_i\\) \\(\\times\\) h = 0.10 + \\(-1\\over 30\\) \\(\\times\\) 0.04<\/p>\n\n\n\n = 0.10 – 0.0013 = 0.0987<\/p>\n\n\n\n = 0.099 ppm<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" Question : Concentration of \\(SO_2\\) (in ppm) Frequency 0.00 – 0.04 4 0.04 – 0.08 9 0.08 – 0.12 9 0.12 – 0.16 2 0.16 – 0.20 4 0.20 – 0.24 2 Solution : Let the assumed mean a = 0.10 Concentration of \\(SO_2\\) (in ppm) Frequency (\\(f_i\\)) Mid – Value (\\(x_i\\)) \\(u_i\\) = \\(x_i …<\/p>\n |