Example 1 : <\/span> If mean of the seies \\(x_1\\), \\(x^2\\), ….. , \\(x_n\\) is \\(\\bar{x}\\), then the mean of the series \\(x_i\\) + 2i, i = 1, 2, ……, n will be-<\/p>\n Solution : <\/span>As given \\(\\bar{x}\\) = \\(x_1 + x_2 + …. + x_n\\over n\\) Example 2 : <\/span> A student obtained 75%, 80%, 85% marks in three subjects. If the marks of another subject are added then his average marks can not be less than-<\/p>\n Solution : <\/span> Total marks obtained from three subjects out of 300 = 75 + 80 + 85 = 240 Example 3 : <\/span> The mean and variance of 5 observations of an experiment are 4 and 5.2 respectively. If from these observations three are 1, 2 and 6, then remaining will be-<\/p>\n Solution : <\/span>As given \\(\\bar{x}\\) = 4, n = 5 and \\({\\sigma}^2\\) = 5.2. If the remaining observations are \\(x_1\\), \\(x_2\\) then Practice these given statistics examples to test your knowledge on concepts of statistics.<\/p>\n <\/div>\n <\/div>\n","protected":false},"excerpt":{"rendered":" Here you will learn some statistics examples for better understanding of statistics concepts. Example 1 : If mean of the seies \\(x_1\\), \\(x^2\\), ….. , \\(x_n\\) is \\(\\bar{x}\\), then the mean of the series \\(x_i\\) + 2i, i = 1, 2, ……, n will be- Solution : As given \\(\\bar{x}\\) = \\(x_1 + x_2 + …<\/p>\n
\n\t\t\t\tIf the mean of the series \\(x_i\\) + 2i, i = 1, 2, ….., n be \\(\\bar{X}\\), then
\n\t\t\t\t\\(\\bar{X}\\) = \\((x_1+2) + (x_2+2.2) + (x_3+2.3) + …. + (x_n + 2.n)\\over n\\)
\n\t\t\t\t = \\(x_1 + x_2 + …. + x_n\\over n\\) + \\(2(1+2+3+….+n)\\over n\\)
\n\t\t\t\t = \\(\\bar{x}\\) + \\(2n(n+1)\\over 2n\\)
\n\t\t\t\t = \\(\\bar{x}\\) + n + 1.<\/p>\n
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if the marks of another subject is added then the total marks obtained out of 400 is greater than 240
if marks obtained in fourth subject is 0 then
minimum average marks = \\(240\\over 400\\)\\(\\times\\)100 = 60%\n <\/p>
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\\({\\sigma}^2\\) = \\(\\sum{(x_i – \\bar{x})}^2\\over n\\) = 5.2
\\(\\implies\\) \\({(x_1-4)}^2 + {(x_2-4)}^2 + {(1-4)}^2 + {2-4)}^2 + {(6-4)}^2\\over 5\\) = 5.2
\\(\\implies\\) \\({(x_1-4)}^2 + {(x_2-4)}^2\\) = 9 …..(1)
Also \\(\\bar{x}\\) = 4 \\(\\implies\\) \\(x_1 + x_2 + 1 + 2 + 6\\over 5\\) = 4 \\(\\implies\\) \\(x_1 + x_2\\) = 11 …..(2)
from eq.(1), (2) \\(x_1\\), \\(x_2\\) = 4, 7<\/p>\n
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