{"id":6303,"date":"2021-10-12T16:53:39","date_gmt":"2021-10-12T11:23:39","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6303"},"modified":"2021-10-12T22:50:33","modified_gmt":"2021-10-12T17:20:33","slug":"equation-of-line-parallel-to-a-line","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/equation-of-line-parallel-to-a-line\/","title":{"rendered":"Equation of Line Parallel to a Line"},"content":{"rendered":"
Here you will learn what is the equation of line parallel to a given line with examples.<\/p>\n
Let’s begin –<\/p>\n
\nThe equation of the line parallel to a given line ax + by + c = 0 is<\/p>\n
ax + by + \\(\\lambda\\),<\/p>\n
where \\(\\lambda\\) is a constant.<\/p>\n<\/blockquote>\n
Proof<\/strong> :<\/p>\n
\nLet m be the slope of the line ax + by + c = 0, Then,<\/p>\n
m = -\\(a\\over b\\)<\/p>\n
Since the required line is parallel to the given line, the slope of the required line is also m.<\/p>\n
Let \\(c_1\\) be the y-intercept of the required line. Then, its equation is<\/p>\n
y = mx + \\(c_1\\)<\/p>\n
y = -\\(a\\over b\\)x + \\(c_1\\)<\/p>\n
\\(\\implies\\) ax + by – b\\(c_1\\) = 0<\/p>\n
\\(\\implies\\) ax + by + \\(\\lambda\\) = 0, where \\(\\lambda\\) = -b\\(c_1\\) = constant.<\/p>\n<\/blockquote>\n
Note<\/strong> : To write a line parallel to any given line we keep the expression containing x and y same and simply replace the given constant by a new constant \\(\\lambda\\). The value of \\(\\lambda\\) can be determined by some given condition.<\/p>\n
Example<\/strong><\/span> : Find the equation of line which is parallal to the line 3x – 2y + 5 = 0 and passes through the point (5, -6).<\/p>\n
Solution<\/strong><\/span> : The line parallel to the line 3x – 2y + 5 = 0 is<\/p>\n
3x – 3y + \\(\\lambda\\) = 0 …………..(i)<\/p>\n
This passes through (5, -6)<\/p>\n
\\(\\therefore\\) 3 \\(\\times\\) 5 – 2 \\(\\times\\) -6 + \\(\\lambda\\) = 0<\/p>\n
\\(\\implies\\) \\(\\lambda\\) = -27.<\/p>\n
Putting \\(\\lambda\\) = -27 in (i) we get, <\/p>\n
3x – 3y – 27 = 0, which is the required equation of line.<\/p>\n\n\n