{"id":6376,"date":"2021-10-13T18:09:56","date_gmt":"2021-10-13T12:39:56","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6376"},"modified":"2021-10-14T22:46:57","modified_gmt":"2021-10-14T17:16:57","slug":"equation-of-plane-parallel-to-plane","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/equation-of-plane-parallel-to-plane\/","title":{"rendered":"Equation of Plane Parallel to Plane"},"content":{"rendered":"
Here you will learn equation of plane parallel to plane with examples.<\/p>\n
Let’s begin – <\/p>\n
Since parallel planes have the common normal, therefore equation of a plane parallel to the plane \\(\\vec{r}\\).\\(\\vec{n}\\) = \\(\\vec{d_1}\\) is<\/p>\n
\n\\(\\vec{r}\\).\\(\\vec{n}\\) = \\(\\vec{d_2}\\)<\/p>\n<\/blockquote>\n
where \\(\\vec{d_2}\\) is constant determined by the given condition.<\/p>\n
Example<\/strong><\/span> : Find the equation of plane passing through the point \\(\\hat{i} + \\hat{j} + \\hat{k}\\) and parallel to the plane \\(\\vec{r}\\).\\(2\\hat{i} – \\hat{j} + 2\\hat{k}\\) = 5.<\/p>\n
Solution<\/span><\/strong> : The equation of a plane parallal to the plane \\(\\vec{r}\\).(\\(2\\hat{i} – \\hat{j} + 2\\hat{k}\\)) = 5 is<\/p>\n
\\(\\vec{r}\\).(\\(2\\hat{i} – \\hat{j} + 2\\hat{k}\\)) = d ………(i)<\/p>\n
If it passes through \\(\\hat{i} + \\hat{j} + \\hat{k}\\), then<\/p>\n
(\\(\\hat{i} + \\hat{j} + \\hat{k}\\)).(\\(2\\hat{i} – \\hat{j} + 2\\hat{k}\\)) = d \\(\\implies\\) 2 – 1 + 2 = d \\(\\implies\\) d = 3<\/p>\n
Putting d = 3 in (i), we obtain \\(\\vec{r}\\).(\\(2\\hat{i} – \\hat{j} + 2\\hat{k}\\)) = 3 as the equation of the required plane.<\/p>\n
(b) Cartesian Form<\/h3>\n
Let ax + by + cz + d = 0 be the cartesian equation of a plane. Then, direction ratios of its normal are proportional to a, b, c.<\/p>\n
Since parallel planes have common normals.<\/p>\n
Therefore, the direction ratios of the normal to the parallel plane are also proportional to a, b, c.<\/p>\n
Thus, the equation of plane parallal to the plane ax + by + cz + d = 0 is <\/p>\n
\nax + by + cz + k = 0,<\/p>\n<\/blockquote>\n
where k is an arbitrary constant and is determined by the given condition.<\/p>\n
Example<\/strong><\/span> : Find the equation of plane passing through the point (1, 4, -2) and parallal to the plane -2x + y – 3z = 7.<\/p>\n
Solution<\/span><\/strong> : Let the equation of a plane parallal to the plane -2x + y – 3z = 7 be<\/p>\n
-2x + y – 3z + k = 7 ………(i)<\/p>\n
If it passes through (1, 4, -2), then<\/p>\n
(-2)(1) + 4 – 3(-2) + k = 0 \\(\\implies\\) k = -8<\/p>\n
Putting k = -8 in (i), we obtain -2x + y – 3z – 8 = 0 as the equation of the required plane.<\/p>\n\n\n