{"id":6669,"date":"2021-10-19T15:34:22","date_gmt":"2021-10-19T10:04:22","guid":{"rendered":"https:\/\/mathemerize.com\/?p=6669"},"modified":"2021-11-27T23:34:10","modified_gmt":"2021-11-27T18:04:10","slug":"what-is-quadratic-equation-in-standard-form","status":"publish","type":"post","link":"https:\/\/mathemerize.com\/what-is-quadratic-equation-in-standard-form\/","title":{"rendered":"What is Quadratic Equation in Standard Form"},"content":{"rendered":"
Here you will learn quadratic equation concepts and what is quadratic equation in standard form.<\/p>\n
Let’s begin – <\/p>\n
If p(x) is a quadratic polynomial, then p(x) = 0 is called a quadratic equation.<\/p>\n
For example, \\(x^2 + 2x – 8\\) = 0, \\(x^2 – 5x + 6\\) = 0 are quadratic equations.<\/p>\n
The general form of quadratic equation is \\(ax^2 + bx + c\\) = 0. where a, b, c \\(\\in\\) R and a \\(\\ne\\) 0.<\/p>\n
The equation of the form \\(ax^2 + bx + c\\) = 0, a \\(\\ne\\) 0 is known as standard equation.<\/p>\n
For example, \\(5x^2 + 3x + 6\\) = 0 is a quadratic equation in the standard form.<\/p>\n
1). Write down the given equation in the form f(x) = 0.<\/p>\n
2). (a) If f(x) is a polynomial, then observe its degree.<\/p>\n
(b) If f(x) is not a polynomial, then first make it poynomial and then observe its degree.<\/p>\n
3). If degree of the polynomial is 2, then the given equation is quadratic.<\/p>\n
Example<\/strong><\/span> : Which of the following are quadratic equation ?<\/p>\n (i) \\(x^2 -6x – 4\\) = 0<\/p>\n (ii) x + 2 = 0<\/p>\n (iii) x + \\(1\\over x\\) = 1, x \\(\\ne\\) 0<\/p>\n (iv) \\(x^2\\) + \\(1\\over x\\) = 1, x \\(\\ne\\) 0<\/p>\n Solution<\/span><\/strong> : <\/p>\n (i) p(x) = \\(x^2 -6x – 4\\) is polynomial with degree 2.<\/p>\n \\(\\therefore\\) \\(x^2 -6x – 4\\) = 0 is a quadratic equation.<\/p>\n (ii) p(x) = x + 2 is polynomial with degree 1.<\/p>\n \\(\\therefore\\) x + 2 = 0 is not a quadratic equation.<\/p>\n (iii) x + \\(1\\over x\\) = 1 \\(\\implies\\) \\(x^2 + 1\\over x\\) = 1 \\(\\implies\\) \\(x^2 +1\\) = x \\(\\implies\\) \\(x^2 – x + 1\\) = 0<\/p>\n Since, here p(x) = \\(x^2 – x + 1\\) is polynomial with degree 2.<\/p>\n \\(\\therefore\\) \\(x^2 – x + 1\\) = 0 is a quadratic equation.<\/p>\n (iv) \\(x^2\\) + \\(1\\over x\\) = 1 \\(\\implies\\) \\(x^3 + 1\\over x\\) = 1 \\(\\implies\\) \\(x^3 +1\\) = x \\(\\implies\\) \\(x^3 – x + 1\\) = 0<\/p>\n Here, p(x) = \\(x^3 – x + 1\\) is polynomial with degree 3.<\/p>\n \\(\\therefore\\) \\(x^3 – x + 1\\) = 0 is not a quadratic equation.<\/p>\n\n\n